Methods · Hypothesis testing · Distribution fitting

Index of Dispersion Test for Count Data

The index of dispersion test checks whether counts fit a Poisson distribution by referring the sum of squared deviations divided by the mean to a chi-square distribution with n - 1 degrees of freedom.

산포 지수 검정은 편차 제곱합을 평균으로 나눈 값을 자유도 n−1 의 카이제곱 분포와 비교해 계수 자료가 포아송 분포와 맞는지 판정하는 검정입니다.

Are my count data overdispersed relative to a Poisson distribution, and should I use a negative binomial model?

계수 자료가 포아송보다 과대산포되어 있는지, 음이항 모형을 써야 하는지 어떻게 확인하나요?

Under a Poisson model the variance equals the mean, so D = sum((x - mean)^2) / mean follows a chi-square distribution with n - 1 degrees of freedom; large values indicate overdispersion and small values underdispersion. A likelihood-ratio test of the negative binomial against the Poisson, with a halved p value because the dispersion parameter lies on the boundary, gives a second view.

When to use Index of Dispersion Test for Count Data

When to use something else

Assumptions and requirements

What the analysis reports

How to report it

The index of dispersion test indicated overdispersion (mean = [value], variance = [value]), D = [value], chi2([df]) p = [value], and the negative binomial fitted better than the Poisson, LR = [value], p = [value].

Related methods

Run Index of Dispersion Test for Count Data on Quorant

Data you need
a table (CSV or Excel) with an outcome variable
Price
150 credits for one analysis up to 10,000 rows (complexity level 1); larger or wider data costs more. Optional methodologist review: 900 credits.
Checking
Checked by property tests in every deployment
Before you pay
A free pre-analysis diagnosis checks your data and gives an exact quote; nothing is deducted until you approve it.

Method ID Q11078 · Reviewed 2026-10-25